Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 663379
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T23:28:59+00:00 2026-05-13T23:28:59+00:00

I have a simple question how do I remove a \ with regex? Thanks

  • 0

I have a simple question how do I remove a \ with regex?

Thanks

I have tried it like this .replace(/\\/ig, '');

I am using javascript and classic asp

Now it works: .replace(/\\/ig, ''); somehow the first time I tried it, it were not working! – Thanks for all the quick answers!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T23:29:00+00:00Added an answer on May 13, 2026 at 11:29 pm

    I tested out the following and it worked (in a test bench) on the first \ (due to "\\"), but not the second \ (because it was in a string, thus acting as an escape character).

    <script type="text/javascript">
    var str="\\ \ ";
    document.write(str.replace(/\\/ig,"replaced"));
    </script>
    

    Are you sure that the \ you wish to replace is not just acting as an escape character and doesn’t really exist in the output?

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Simple question, i have this DIV right, 400 * 250 px. And i have
This is probably an overly simple question, but I have a blog Creating Wealth
There is probably a simple solution to this question, but if i have the
I'm new to Objective C and I have a simple question about memory management.
Pretty simple question (probably) but I guess since im new to python im not
hey guys, probably simple question for the most of you. I can't figure out
I have a simple data flow. The source is a small flat file with
Hello I am building a simple aggregator script and I am trying to have
I have two span tags that contain content. The first span tag will hold
I'm creating a very simple phone directory for a homework assignment but I'm stuck.

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.