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Home/ Questions/Q 8715859
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T05:56:47+00:00 2026-06-13T05:56:47+00:00

I have a simple question on the variable’s types in C/C++, namely one can

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I have a simple question on the variable’s types in C/C++, namely
one can declare such types as

int32_t, int64_t, etc.

My question is what does “t” mean in these types and what’s the difference from
the usual types, like int32, int64.

Thanks!

…

Sorry, I don’t know how to answer properly to all who responded to my question instead of writing separate comments. Anyway, thanks to all of you for your replies.
Well, I have to say that I am parsing a code and I am a newbie in C/C++ (not C#)

Concerning int32_t etc they seem indeed to be defined separately in a header file:

#include <stdint.h>
#ifdef _FAST_
#define SHORT  uint_fast16_t
#define INT    uint_fast32_t
#define LONG   uint_fast64_t
#else
#define SHORT  uint16_t
#define INT    uint32_t
#define LONG   uint64_t
#endif

Could someone explain what this construction means?

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  1. Editorial Team
    Editorial Team
    2026-06-13T05:56:48+00:00Added an answer on June 13, 2026 at 5:56 am

    There are no built in types like Int32_t and Int64_t, and there are no magic suffix _t that you can add to an existing type.

    The types Int32_t and Int64_t has to be defined somewhere in your code. They are probably using the Int32 and Int64 types in some way, but there is no magic involved just because the type names contains other type names. They could just as well be named ABigNumber and ABiggerNumber as far as the compiler is concerned.

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