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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:34:07+00:00 2026-06-15T14:34:07+00:00

I have a simple question, that I feel should have a simple solution. How

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I have a simple question, that I feel should have a simple solution. How do I format a floating number so that only the numbers after the decimal point show? I would prefer to use ‘{}’.format to accomplish this.

>>> n = 0.12345
>>> n
0.12345
>>> str(n)[1:]
'.12345'
>>> '{}'.format(n)
'0.12345'
>>> '{}'.format(str(n)[1:])
'.12345'

I know I can use str(n)[1:], but I’d prefer not to have to convert the number to a string.

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:34:09+00:00Added an answer on June 15, 2026 at 2:34 pm

    I do not think there is a format string which removes the zero. However, you could use lstrip:

    In [25]: n = 0.12345
    In [26]: '{:.3f}'.format(n).lstrip('0')
    Out[26]: '.123'
    

    At least that is safer than str(n)[1:], which would remove a signficiant digit if n were equal to a number bigger than 1 or less than -1.

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