Question

I have a simple regex which checks an entire string for a function declaration. So in this code:

public function Test($name)
{
    echo 'In test';
}

It will find the first part:

function Test($name)
{

And it replaces that with a custom piece:

function Test($name)
{
    echo 'New piece';

Which eventually makes my code look like this:

public function Test($name)
{
    echo 'New piece';
    echo 'In test';
}

This all works perfectly fine with this regex:

preg_match_all ( '/function(.*?)\{/s', $source, $matches )

---

The problem is, is that i want to ignore everything when the regex sees a script tag. So in this case, this source:

public function Test($name) //<--- Match found!
{
    echo 'In test';
}

<script type="text/javascript"> //<--- Script tag found, dont do any matches!
$(function() {
    function Test()
    {
        var bla = "In js";
    }
});
</script> //<--- Closed tag, start searching for matches again.

public function Test($name) //<--- Match found!
{
    echo 'In test';
}

How can i do this in my regex?

Answer 1

As mentioned in the comments:

If your php functions always have a visibility modifier like public you could do:

(?:public|protected|private)\s+function\s+\w+\(.*?\)\s*\{

Otherwise, you could strip the script part first.
Something like:

$text = preg_replace('/<script(?:(?!<\/script>).)*<\/script>/s','',$text);