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Home/ Questions/Q 6337381
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T19:14:36+00:00 2026-05-24T19:14:36+00:00

I have a simple ViewPager example that just places a TextView with the current

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I have a simple ViewPager example that just places a TextView with the current position. I want to adapt this to work in an existing app I have written.

My app currently uses a layout and then adjusts the values as needed. I want to use this layout with the ViewPager, but I currently am unable to get the layout.

When constructing my PagerAdapter I pass in the context from the main activity.

I am unable to use findViewById to get my layout though.

Can someone suggest the correct way to get it?

public Object instantiateItem(View collection, int position)
{
    LinearLayout info = (LinearLayout)((Activity)_context).findViewById(R.id.linearlayout);

    ((ViewPager) collection).addView(info, 0);

    return info;
}

The code above is from my PagerAdapter. I have a layout that I want to use as the pages for the pager, which I want to populate with info into the layouts TextViews and other views…

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  1. Editorial Team
    Editorial Team
    2026-05-24T19:14:37+00:00Added an answer on May 24, 2026 at 7:14 pm

    I would pass a LayoutInflater to the adapter and then on the instantiateItem, I would create the View as I wished.

    Even if it doesn’t compile, could you post the code?

    And btw have you check out this implementation? It helped me once because I was forgetting the line

       ((ViewPager) collection).addView( some view...,0);
    

    in the instantiateItem method.

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