Question

I have a simple webview which loads a page. This page has a few links that opens within the webview. That’s what it supposed to do, so it’s working all fine.

But there is one single link from that page which should load as a popup, so I want it to open in the normal browser when people click it. But as I stated, all links are opening in the webview, so that link does it also.

My question is, how can I make this link open in the normal browser as a kind of a popup? Is it even possible? The link is variable so it’s changing always, it cannot be hardcoded within the application to open in a new browser browser.

Is it possible and how can I do it?

Answer 1

Here’s an example of overriding webview loading to stay within your webview or to leave:

import android.app.Activity;
import android.os.Bundle;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class TestWebViewActivity extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);


        WebView webView = (WebView) findViewById(R.id.webview);
        webView.setWebViewClient(new MyWebViewClient());
    }
}


class MyWebViewClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if(url.contains("somePartOfYourUniqueUrl")){ // Could be cleverer and use a regex
            return super.shouldOverrideUrlLoading(view, url); // Leave webview and use browser
        } else {
            view.loadUrl(url); // Stay within this webview and load url
            return true;
        }
    }
}