Question

I have a simple xml document that looks like the following snippet. I need to write a XSLT transform that basically ‘unpivots’ this document based on some of the attributes.

<?xml version='1.0' encoding='utf-8' ?> <root xmlns:z='foo'>     <z:row A='1' X='2' Y='n1' Z='500'/>     <z:row A='2' X='5' Y='n2' Z='1500'/> </root> 

This is what I expect the output to be –

<?xml version='1.0' encoding='utf-8' ?> <root xmlns:z='foo'>     <z:row A='1' X='2'  />     <z:row A='1' Y='n1' />     <z:row A='1' Z='500'/>     <z:row A='2' X='5' />     <z:row A='2' Y='n2'/>     <z:row A='2' Z='1500'/> </root> 

Appreciate your help.

Answer 1

<xsl:template match='row'>     <row A='{$A}' X='{$X}' />     <row A='{$A}' Y='{$Y}' />     <row A='{$A}' Z='{$Z}' /> </xsl:template> 

Plus obvious boilerplate.