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Asked: 2026-05-11T06:06:47+00:00

I have a simple XML with two levels (Header and Line) of tags such

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I have a simple XML with two levels (Header and Line) of tags such as:

<?xml version="1.0"?> <Header>     <line>Line 1</line>     <line>Line 2</line>     <line>Line 3</line>     <line>Line 4</line>     <line>Line 5</line>     <line>Line 6</line>     <line>Line 7</line>     <line>Line 8</line>     <line>Line 9</line> </Header>

I need to group the lines on sets of X (X=3 for example) lines so that my output is the following:

<?xml version="1.0"?> <Header>     <set>         <line>Line 1</line>         <line>Line 2</line>         <line>Line 3</line>     </set>     <set>         <line>Line 4</line>         <line>Line 5</line>         <line>Line 6</line>     </set>     <set>         <line>Line 7</line>         <line>Line 8</line>         <line>Line 9</line>     </set> </Header>

How do I write a XSLT that can do this kind of transformation?

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  1. The following transformation produces the required result:

    <xsl:stylesheet version='1.0'   xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>  <xsl:output omit-xml-declaration='yes' indent='yes'/>   <xsl:variable name='vN' select='3'/>    <xsl:template match='/*'>     <xsl:copy>       <xsl:apply-templates             select='line[position() mod $vN = 1]'/>     </xsl:copy>   </xsl:template>    <xsl:template match='line'>     <set>       <xsl:apply-templates mode='copy' select=         '.         |          following-sibling::line[position() &lt; $vN]'/>     </set>   </xsl:template>      <xsl:template match='line' mode='copy'>       <xsl:copy-of select='.'/>     </xsl:template> </xsl:stylesheet>

    When applied on the provided XML document:

    <Header>     <line>Line 1</line>     <line>Line 2</line>     <line>Line 3</line>     <line>Line 4</line>     <line>Line 5</line>     <line>Line 6</line>     <line>Line 7</line>     <line>Line 8</line>     <line>Line 9</line> </Header>

    the result is:

    <Header>   <set>     <line>Line 1</line>     <line>Line 2</line>     <line>Line 3</line>   </set>   <set>     <line>Line 4</line>     <line>Line 5</line>     <line>Line 6</line>   </set>   <set>     <line>Line 7</line>     <line>Line 8</line>     <line>Line 9</line>   </set> </Header>

    Do note the following:

    1. The use of the XPath mod operator to find out the first line element in every group of vN elements.

    2. The use of modes, in order to be able to process different line elements by different templates

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