Question

I have a (simplified) table that is structured like so:

Table: ItemData

PK | ScanCode | StoreFK | Retail | ReceiptAlias
1  | 100101   | 1       | 4.99   | Milk
4  | 100101   | 2       | 4.99   | Milk
7  | 100101   | 3       | 0.99   | Milk
2  | 100102   | 1       | 6.99   | Eggs
5  | 100102   | 2       | 6.99   | Eggs
8  | 100102   | 3       | 6.99   | Eggs
3  | 100103   | 1       | 7.99   | Bread
6  | 100103   | 2       | 8.99   | Bread
9  | 100103   | 3       | 9.99   | Bread

I can use the following SQL query to get the following return results, which shows all the items that have a different retail at one or more stores: see this previously asked question

SQL Query:

SELECT   im.INV_ScanCode     AS ScanCode,
         name.ItemData AS im
GROUP BY ScanCode, Receipt_Alias
HAVING   COUNT(DISTINCT im.Retail) > 1
ORDER BY ScanCode

Current Return Results:

ScanCode | Receipt_Alias 
100101   | Milk
100103   | Bread

I would like to return all the items that have a different retail at one or more stores AND the retail at each store location:

Desired Return Results:

ScanCode | Receipt_Alias | Str_1 | Str_2 | Str_3
100101   | Milk          | 4.99  | 4.99  | 0.99
100103   | Bread         | 7.99  | 8.99  | 9.99

How would I change my SQL query to include the retail at each store location?

Answer 1

SELECT  ScanCode as ItemID,
        ReceiptAlias,
        MAX(CASE WHEN StoreFK = 1 THEN Retail ELSE NULL END) Store_1,
        MAX(CASE WHEN StoreFK = 2 THEN Retail ELSE NULL END) Store_2,
        MAX(CASE WHEN StoreFK = 3 THEN Retail ELSE NULL END) Store_3
FROM    ItemData
GROUP   BY ScanCode, ReceiptAlias
HAVING  COUNT(DISTINCT Retail) > 1

• SQLFiddle Demo