Question

I have a SlidingDrawer element which contains a RelativeLayout element which contains some Button child elements:

<SlidingDrawer>
  <RelativeLayout>
    <LinearLayout>
      <Button android:background="@drawable/foo.xml" android:duplicateParentState="false">
      <Button android:background="@drawable/bar.xml" android:duplicateParentState="false">
    </LinearLayout>
  </RelativeLayout>
</SlidingDrawer>

foo.xml and bar.xml have selectors which apply different images depending on the state:

<selector xmlns:android="http://schemas.android.com/apk/res/android">
  <item android:state_focused="true" android:drawable="@drawable/foo_selected" />
  <item android:state_pressed="true" android:drawable="@drawable/foo_selected" />
  <item android:state_enabled="false" android:drawable="@drawable/foo_disabled" />
  <item android:drawable="@drawable/foo_normal" /> 
</selector>

The problem I am seeing is that when I click on the sliding drawer handle, the pressed state gets triggered for the buttons and they look pressed too, even though I’ve specified duplicateParentState to false.

Answer 1

Override the LinearLayout class with a subclass. In that subclass override the setPressed method and do nothing like so:

public class UnpressableLinearLayout extends LinearLayout
{
    @Override
    public void setPressed(boolean pressed)
    {
        // Do nothing here. Specifically, do not propagate this message along
        // to our children so they do not incorrectly display a pressed state
        // just because one of their ancestors got pressed.
    }
}

Replace LinearLayout with an instance of UnpressableLinearLayout.