I have a slight problem. I need to parse a file and populate a web banner with the results. Problem is, the file is called : “_banner_products.php” and it’s contents are as follows:
<?php header('Content-Type:text/xml'); ?><?php echo '<?xml version="1.0" encoding="UTF-8"?>'; ?>
<carouselle>
<firstLayer>
<layerName>Leica Disto X310</layerName>
<layerProduct>Disto X310</layerProduct>
<layerPic>http://www.leicaestonia.ee/extensions/boxes_design/flashpics/1334482548.jpg</layerPic>
<layerPrice>0,-</layerPrice>
<layerPriceOld></layerPriceOld>
<layerLink>http://www.leicaestonia.ee/index.php?id=11627</layerLink>
<layerTimer>01.05.2012 00:00</layerTimer>
</firstLayer>
<firstLayer>
.....
.....
</firstLayer>
</carouselle>
How can I loop through this file to group all the “firstLayer” children into one and so on..
If I just use:
$file = fopen("_banner_products.php", "r");
while (!feof($file)){
$line = fgets($file);
}
simplexml_load_file throws this-
“_banner_products.php:1: parser error : Start tag expected, ‘<‘ “
Then I only get the contents of the <…> tags meaning there is no way for me to differentiate if I am out of the scope already.
Thanks for anyone responding. If anything is unclear I´ll try to explain more.
EDIT.
Thank you for the solution, indeed using the full URL worked:
simplexml_load_file("http://localhost/MySite/_banner_products.php");
You are having issue because
simplexml_load_fileis treating your file like a local xml file .. what you need to do is add the full URLExample
Use Case getting
layerNamefor example_banner_products.phpview details