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Home/ Questions/Q 9008407
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T01:55:52+00:00 2026-06-16T01:55:52+00:00

I have a slight problem in that I am passing several SQL Server Like

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I have a slight problem in that I am passing several SQL Server Like queries (which I don’t have control over) in my .Net application and I need to escape some of the characters to make them literals for the database.

For example, suppose the field I am trying to query looks something like:

This_is [a] long_text field with [literal] characters in it

And my query looks something like this:

SELECT * FROM [MyTable] where [MyField] Like 'This_% [literal]%'

Now, this should get that data, the challenge is that the _ and [ characters are not seen by SQL Server as the literal characters, so I have to update my query to:

SELECT * FROM [MyTable] where [MyField] Like 'This[_]% [[]literal]%'

And then it works.


So, my question is that I would like to write a VB.Net function that uses RegEx to find the Like part of the statement and then to replace the characters.

Something along the lines of:

Public Function ConvertQuery(strSQL as string)

... Some kind of Regex that searches for the word "Like" 
    and then takes everytihng between the 2 "'" characters
    Then replaces the "_" with "[_]" and "[" with "[[]"

Return ChangedString
End Function

I know I am giving REALLY bad details, I know what i want, I just can’t figure out how to do it with RegEx.

ALSO, if there is a smarter way to do this with SQL Server Like statments, please also let me know!!!

Thanks!!

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  1. Editorial Team
    Editorial Team
    2026-06-16T01:55:53+00:00Added an answer on June 16, 2026 at 1:55 am

    Seeing that C# tag, I assume you are OK with an answer in C#.

    string input = "This_is [a] long_text field with [literal] characters in it";
    var output = Regex.Replace(input, @"[_\[]","[$0]");
    

    EDIT

    string input = "SELECT * FROM [MyTable] where [MyField] Like 'This_% [literal]'";
    var output = Regex.Replace(input, @"(?<=Like[ ]*\'.+?)[_\[]", "[$0]");
    
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