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Home/ Questions/Q 3311848
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:55:30+00:00 2026-05-17T21:55:30+00:00

I have a slow function that does an AJAX request: function X(param1,param2){ var params={

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I have a slow function that does an AJAX request:

function X(param1,param2){
var params={
    type: "POST",
    url: "./ajax/useful.php",
    data: "param1="+param1+"&param2="+param2,
    success: function(msg){
      //do something
    }
  };
  var result=$.ajax(params).responseText;
}

Everything works fine when I call X(“asdf”,”qwerty”).

Now, what I want to do is to be able to call function X as follows:

function X(param1,param2,function(){alert('hi');}){
var params={
    type: "POST",
    url: "./ajax/useful.php",
    data: "param1="+param1+"&param2="+param2,
    success: function(msg){
      /////
      //I want to be able call the function in the 3rd parameter (alert in this case)
      /////
    }
  };
  var result=$.ajax(params).responseText;
}

Now you might say why don’t I just call alert(‘hi’) directly inside the success. Sure I can do this, but I want to be able to vary what goes on inside the called function (not just a simple alert(‘hi’), depending on who’s calling X.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:55:30+00:00Added an answer on May 17, 2026 at 9:55 pm

    You declare your X function like this:

    function X(param1,param2,callback){
    

    …use the callback like this:

    success: function(msg){
        callback();
    }
    

    …and call X like this:

    X('a', 'b', function(){alert('hi');});
    

    This works because your success handler is a closure over the data within your X function, including its arguments. It has a live reference to that information (even after X returns), and so later when the Ajax call completes, it can still use the callback argument. More on closures here: Closures are not complicated

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