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Home/ Questions/Q 719555
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:39:21+00:00 2026-05-14T05:39:21+00:00

I have a small app I’m working on where I’m trying to use Django’s

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I have a small app I’m working on where I’m trying to use Django’s built in filesizeformat. Currently, the format looks like this: {{ value|filesizeformat }}. I understand I need to define this in my view.py file but, I can’t seem to figure out how to do that. I’ve tried to use the syntax below:

def filesizeformat(bytes):
    """
    Formats the value like a 'human-readable' file size (i.e. 13 KB, 4.1 MB,
    102 bytes, etc).
    """
    try:
        bytes = float(bytes)
    except (TypeError,ValueError,UnicodeDecodeError):
        return u"0 bytes"

    if bytes < 1024:
        return ungettext("%(size)d byte", "%(size)d bytes", bytes) % {'size': bytes}
    if bytes < 1024 * 1024:
        return ugettext("%.1f KB") % (bytes / 1024)
    if bytes < 1024 * 1024 * 1024:
        return ugettext("%.1f MB") % (bytes / (1024 * 1024))
    return ugettext("%.1f GB") % (bytes / (1024 * 1024 * 1024))
filesizeformat.is_safe = True 

I’ve then replaced ‘value’ with ‘bytes’ in the template but, this does not seem to work. Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:39:21+00:00Added an answer on May 14, 2026 at 5:39 am

    filesizeformat is a built-in filter, you do not need to implement it yourself. You should provide the value into the template, for example:

    {% for page in pages %}
        <li>page.name {{page.size|filesizeformat}}</li>
    {% endfor %}
    

    Now when you render the template from the view provide a pages argument which is a list of dicts like:

    [{'name': 'page1', 'size': 10000}, {'name': 'page2', 'size': 5023034}]
    

    And so on.

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