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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:57:36+00:00 2026-05-13T05:57:36+00:00

I have a small question in JavaScript. Here is a declaration: function answerToLifeUniverseAndEverything() {

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I have a small question in JavaScript.

Here is a declaration:

function answerToLifeUniverseAndEverything() {
   return 42;
}

var myLife = answerToLifeUniverseAndEverything();

If I do console.log(myLife), it will print 42, as I am just invoking the same instance of function resulting in 42 as the answer. (Basic rule on JavaScript that only references of objects are passed and not the object.)

Now, on the other, hand if I do:

var myLife = new answerToLifeUniverseAndEverything();

then I can’t invoke the function; instead, myLife becomes just an object? I understand that this is a new copy of the same function object and not a reference, but why can’t I invoke the method?

Can you please clarify the basic fundamental I am missing here?

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:57:37+00:00Added an answer on May 13, 2026 at 5:57 am

    By prefixing the call to answerToLifeUniverseAndEverything() with new you are telling JavaScript to invoke the function as a constructor function, similar (internally) to this:

    var newInstance = {};
    var obj = answerToLifeUniverseAndEverything.call(newInstance); // returs 42
    if (typeof obj === 'object') {
      return obj
    } else {
      return newInstance;
    }
    

    JavaScript proceeds to initialize the this variable inside the constructor function to point to a new instance of answerToLifeUniverseAndEverything. Unless you return a different Object yourself, this new instance will get returned, whether you like it or not.

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