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Home/ Questions/Q 7808201
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T03:04:39+00:00 2026-06-02T03:04:39+00:00

I have a smarty template that has a variable set that is a custom

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I have a smarty template that has a variable set that is a custom php class called “survey”. This object has a member variable called “recipientName”. When I print out the variable using the following code:

{$survey->recipientName}

it works fine. The recipient’s name gets printed out, as one would expect. However, if I try to pass that into a function, it does not seem to work right. Take the following code snippet:

{if substr($survey->recipientName,0,3) eq 'Bob'}
    Hello Bob
{else}
    You are not Bob
{/if}

This snippet will always print out “You are not Bob”, even if recipientName is set to “Bob Smith”. As a proof of concept, the following performs as expected:

{if substr("Bob Smith",0,3) eq 'Bob'}
    Hello Bob
{else}
    You are not Bob
{/if}

The above will print out “Hello Bob”.

Similarly, I have noticed weird behavior in other places as well. For example, take the following code snippet:

{assign var="recipname" value="$survey->recipientName"}

This will assign the variable recipname to a value of “->recipientName”. Am I missing something?

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  1. Editorial Team
    Editorial Team
    2026-06-02T03:04:40+00:00Added an answer on June 2, 2026 at 3:04 am

    The substring issue was a non-issue, a simple positioning error.

    The assign issue, however, was due to the quotes around the value. Changing it to {assign var=”recipname” value=$survey->recipientName} fixed it.

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