Question

I have a source like this:

    Exception e = new Exception("Exception");
    IOException ioE = new IOException("An exception cause");
    e.initCause(ioE);

I’m trying to set the cause of the exception “e” and what I get is the exception being set to itself!

I just don’t get it. Does my code make any sense or am I going nuts?

Answer 1

Seems to work:

package com.daniel.test;

import java.io.IOException;

public class Test {

public static void main(String[] args) throws Exception{
    Exception e = new Exception("Exception");
    IOException ioE = new IOException("An exception cause");
    e.initCause(ioE);
    throw e;
    }

}

The output is:

Exception in thread "main" java.lang.Exception: Exception
at com.daniel.test.Test.main(Test.java:8)
Caused by: java.io.IOException: An exception cause
at com.daniel.test.Test.main(Test.java:9)

You can see that the cause is set properly.