Question

I have a spinner like this:

// Spinner 1


final Spinner plan = (Spinner) dialog.findViewById(R.id.spinner1);
strings = getResources().getStringArray(R.array.paymentplan);
sAdapter = new SpinnerAdapter(this,
        android.R.layout.simple_spinner_item, strings);
sAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
plan.setAdapter(sAdapter);

// plan.setAdapter(spinner1Adapter);
plan.setSelection(prefsDisplay.getInt("spinnerSelection1", 0));
plan.setOnItemSelectedListener(new MyOnItemSelectedListenerPlan());

When user clicks, I want it to save state:

  public void onClick(View v) {
                Editor editor2 = prefsPlan.edit();
                int selectedPosition1 = plan.getSelectedItemPosition();
                editor2.putInt("spinnerSelection1", selectedPosition1);
                editor2.commit();


}

It saves the position in SharedPref, but the spinner goes back to default. Anyone see something here?

Answer 1

you are storing spinnerSelection

editor1.putInt("spinnerSelection", selectedPosition);

an accessing spinnerSelection1

prefsDisplay.getInt("spinnerSelection1", 0)

make them consistent.

Update

when you are accessing plan.getSelectedItemPosition(). then spinner is visible? I guess NO.

try to put a public variable for selected position. And update selected position in your MyOnItemSelectedListenerPlan. And then store that position in shared preferences. I guess it solve your problem.