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Home/ Questions/Q 7559285
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T12:35:48+00:00 2026-05-30T12:35:48+00:00

I have a SQL Datestamp like this: 2012-02-20 21:14:54 How would I print out

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I have a SQL Datestamp like this: 2012-02-20 21:14:54

How would I print out the relative date and time in PHP?

e.g.

Occured: a few seconds ago
Occured: 4 minutes ago
Occured: 4 hours ago
Occured: Monday Jan 8th, 2012

After the hours I just want to print out the actual date

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  1. Editorial Team
    Editorial Team
    2026-05-30T12:35:49+00:00Added an answer on May 30, 2026 at 12:35 pm

    Found this after two seconds of Google http://www.mdj.us/web-development/php-programming/another-variation-on-the-time-ago-php-function-use-mysqls-datetime-field-type

    In general you chose a unit of time like seconds, test if the time-difference is smaller then the max-value for this unit (60s) and if so, print out “$timeDifference $unit”. If not you divide the difference by the units max-value and start over with the next higher unit (minutes).

    Example:

    $timeDif = 60*60*5 + 45; // == 5 hours 45 seconds
    
    // 60 seconds in a minute
    if ($timeDif < 60) // false
        return "$timeDif second(s) ago";
    
    // convert seconds to minutes
    $timeDif = floor($timeDif / 60); // == 300 = 5 * 60
    
    // 60 minutes in an hour
    if ($timeDif < 60) // false
        return "$timeDif minute(s) ago";
    
    // convert minutes to hours
    $timeDif = floor($timeDif / 60); // == 5
    
    // 24 hours in a day
    if ($timeDif < 24)
        return "$timeDif hour(s) ago";
    
    // ...
    
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