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Home/ Questions/Q 364461
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:26:26+00:00 2026-05-12T13:26:26+00:00

I have a SQL Server 2000 database with approximately 220 tables. These tables have

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I have a SQL Server 2000 database with approximately 220 tables. These tables have a number foreign key relationships between them. Through performance analysis, we’ve discovered a number of these foreign key relationships are missing indexes. Instead of being reactive to performance problems, I’d like to be pro-active and find all foreign keys that are missing indexes.

How can I programmatically determine which foreign key are missing indexes?

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:26:26+00:00Added an answer on May 12, 2026 at 1:26 pm

    Here is an answer that works for SQL Server 2000 authored by a co-worker:

    /*
    Description:
        This script outputs a table with all the current database un-indexed foreign keys.
    
        The table has three columns ( TableName , ColumnName, ForeignKeyName ) 
        TableName: The table containing the un-indexed foreign key
        ColumnName: The foreign key column that’s not indexed 
        ForeignKeyName: Name of foreign key witch column doesn’t have an index 
        */
    DECLARE 
        @TableName varchar(255),
        @ColumnName varchar(255),
        @ForeignKeyName sysname
    
    SET NOCOUNT ON
    SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED
    
    DECLARE FKColumns_cursor CURSOR Fast_Forward FOR
    SELECT  cu.TABLE_NAME, cu.COLUMN_NAME, cu.CONSTRAINT_NAME
    FROM    INFORMATION_SCHEMA.TABLE_CONSTRAINTS ic 
        INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE cu ON ic.CONSTRAINT_NAME = cu.CONSTRAINT_NAME
    WHERE   ic.CONSTRAINT_TYPE = 'FOREIGN KEY'
    
    CREATE TABLE #temp1(    
        TableName varchar(255),
        ColumnName varchar(255),
        ForeignKeyName sysname
    )
    
    OPEN FKColumns_cursor  
    FETCH NEXT FROM FKColumns_cursor INTO @TableName, @ColumnName, @ForeignKeyName
    
    WHILE @@FETCH_STATUS = 0  
    BEGIN
    
        IF ( SELECT COUNT(*)
        FROM    sysobjects o    
            INNER JOIN sysindexes x ON x.id = o.id
            INNER JOIN  syscolumns c ON o.id = c.id 
            INNER JOIN sysindexkeys xk ON c.colid = xk.colid AND o.id = xk.id AND x.indid = xk.indid
        WHERE   o.type in ('U')
            AND xk.keyno <= x.keycnt
            AND permissions(o.id, c.name) <> 0
            AND (x.status&32) = 0
            AND o.name = @TableName
            AND c.name = @ColumnName
        ) = 0
        BEGIN
            INSERT INTO #temp1 SELECT @TableName, @ColumnName, @ForeignKeyName
        END
    
    
        FETCH NEXT FROM FKColumns_cursor INTO @TableName, @ColumnName, @ForeignKeyName
    END  
    CLOSE FKColumns_cursor  
    DEALLOCATE FKColumns_cursor 
    
    SELECT * FROM #temp1 ORDER BY TableName
    
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