Question

I have a sql statement that is searching my database

"SELECT catelogue.ARTIST, catelogue.TITLE, catelogue.`CAT NO.`, 
catelogue.FORMAT,catelogue.`IMAGE PATH` 
FROM catelogue 
WHERE catelogue.TITLE LIKE '%$search%'"

Now I understand in sql that your percent is your wildcard but I now need the search to search for 100% Summer because this is the title of a cd.

Is there a way to do this so that the percent sign dosn’t affect my other wildcards?

EDIT:

So if I use this

$search = addcslashes(mysql_real_escape_string($search), '%_');

Is there then any need for preg replace

$search = preg_replace("/[^a-zA-Z 0-9\/\\+\.,:?-]+/", "", $search)

And can preg replace be used in conjunction with mysql_real_escape_string?

Answer 1

\% is an escaped “%” character.

Edited:

PHP:

$search = "100\% Summer";

in general use string addcslashes ( string $str , string $charlist ):

$search = "100% Summer";
$search = addcslashes($search, '%_');

Don’t forget to use string mysql_real_escape_string ( string $unescaped_string [, resource $link_identifier ] ) to prevent SQL injection. So the final code might looks like:

$search = "100% Summer";
$search = addcslashes(mysql_real_escape_string($search), '%_');