Question

I have a status table, and another table containing additional data. My object IDs are the PK in the status table, so I need to insert those into the additional data table for each new row.

I need to insert a new row into my statusTable for each new listing, containing just constants.

declare @temp TABLE(listingID int)

insert into statusTable(status, date)
  output Inserted.listingID into @temp
select 1, getdate()
from anotherImportedTable

This gets me enough new listing IDs to use.

I now need to insert the actual listing data into another table, and map each row to one of those listingIDs –

insert into listingExtraData(listingID, data)
select t.listingID, a.data
from @temp t, anotherImportedTable a

Now this obviously doesn’t work, because otherDataTable and the IDs in @temp are unrelated… so I get far too many rows inserted.

How can I insert each row from anotherImportedTable into listingExtraData along with a unique newly created listingID? could I possibly trigger some more sql at the point I do the output in the first block of sql?

edit: thanks for the input so far, here’s what the tables look like:

anotherImportedTable:

data

statusTable:

listingID (pk), status, date

listingExtraData:

data, listingID

You see that I only want to create one entry into statusTable per row in anotherImportedTable, then put one listingID with a row from anotherImportedTable into listingExtraData… I’m thinking that I might have to resort to a cursor perhaps?

Answer 1

Ok, here’s how you can do it (if I’m right about what you actually want to do):

insert into listingExtraData(listingID, data)
select q1.listingID, q2.data
from 
   (select ListingID, ROW_NUMBER() OVER (order by ListingID) as rn from @temp t) as q1
   inner join (select data, ROW_NUMBER() over (order by data) as rn from anotherImportedTable) q2 on q1.rn = q2.rn

In case you matching logic differs you will need to change sorting of anotherImportedTable. In case your match order can not be achieved by ordering anotherImportTable [in one way or another] then you’re out of luck.