Question

I have a string as below:

$str = "/dir1/dir2/dir3/file.txt"

I want to remove the /file.txt from this string.

So that the $str will become.

$str = "/dir1/dir2/dir3"

I am using the following regex. But it is replacing everything.

$str =~ s/\/.*\.txt//;

How can I make regex to look for last ‘/’ instead of first.

What is the correct regular expression for this?

Please note that file.txt is not fixed name. It can be anything like file1.txt, file2.txt, etc.

Answer 1

In this regex

m/(.*)\/[^\/]*$/

the first submatch is the path you are looking for.

EDIT:

If you are looking for substitution user1215106’s soultion is the way to go:

s/\/[^\/]*$//