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Home/ Questions/Q 1113183
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T02:49:06+00:00 2026-05-17T02:49:06+00:00

i have a String displayed on a WebView as Siwy & Para Wino i

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i have a String displayed on a WebView as “Siwy & Para Wino”

i fetch it from url , i got a string “Siwy%2B%2526%2BPara%2BWino”. // be corrected

now i’m trying to use URLDecoder to solve this problem :

String decoded_result = URLDecoder.decode(url); // the url is "Siwy+%26+Para+Wino"

then i print it out , i still saw “Siwy+%26+Para+Wino”

Could anyone tell me why?

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  1. Editorial Team
    Editorial Team
    2026-05-17T02:49:08+00:00Added an answer on May 17, 2026 at 2:49 am

    From the documentation (of URLDecoder):

    This class is used to decode a string which is encoded in the application/x-www-form-urlencoded MIME content type.

    We can look at the specification to see what a form-urlencoded MIME type is:

    The form field names and values are escaped: space characters are replaced by ‘+‘, and then reserved characters are escaped as per [URL]; that is, non-alphanumeric characters are replaced by ‘%HH‘, a percent sign and two hexadecimal digits representing the ASCII code of the character. Line breaks, as in multi-line text field values, are represented as CR LF pairs, i.e. ‘%0D%0A‘.

    Since the specification calls for a percent sign followed by two hexadecimal digits for the ASCII code, the first time you call the decode(String s) method, it converts those into single characters, leaving the two additional characters 26 intact. The value %25 translates to % so the result after the first decoding is %26. Running decode one more time simply translates %26 back into &.

    String decoded_result = URLDecoder.decode(URLDecoder.decode(url));
    

    You can also use the Uri class if you have UTF-8-encoded strings:

    Decodes ‘%’-escaped octets in the given string using the UTF-8 scheme.

    Then use:

     String decoded_result = Uri.decode(Uri.decode(url));
    
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