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Home/ Questions/Q 266565
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T23:27:18+00:00 2026-05-11T23:27:18+00:00

I have a string in the format: ‘nn.nnnnn’ in Python, and I’d like to

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I have a string in the format: ‘nn.nnnnn’ in Python, and I’d like to convert it to an integer.

Direct conversion fails:

>>> s = '23.45678'
>>> i = int(s)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '23.45678'

I can convert it to a decimal by using:

>>> from decimal import *
>>> d = Decimal(s)
>>> print d
23.45678

I could also split on ‘.’, then subtract the decimal from zero, then add that to the whole number … yuck.

But I’d prefer to have it as an int, without unnecessary type conversions or maneuvering.

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  1. Editorial Team
    Editorial Team
    2026-05-11T23:27:18+00:00Added an answer on May 11, 2026 at 11:27 pm

    How about this?

    >>> s = '23.45678'
    >>> int(float(s))
    23
    

    Or…

    >>> int(Decimal(s))
    23
    

    Or…

    >>> int(s.split('.')[0])
    23
    

    I doubt it’s going to get much simpler than that, I’m afraid. Just accept it and move on.

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