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Home/ Questions/Q 8069215
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T12:57:03+00:00 2026-06-05T12:57:03+00:00

I have a string like: str = ‘in europe it costs 250 eur’ or:

  • 0

I have a string like:

str = 'in europe it costs 250 eur'

or:

str = 'in europe it costs a lot (250eu)'

or:

str = 'eureka! I found it and it costs eu250'

or:

str = 'eureka! I found it and it costs 250.00eur'

and so on..

I want to replace both 'eu' and 'eur' with 'euro' when they are followed and preceded by a non-char ([^a-z]) but I don’t want them to be victims of replacement. How do I accomplish that using sub or other methods?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T12:57:05+00:00Added an answer on June 5, 2026 at 12:57 pm

    First we compile an array we use as the set of test cases:

    test_input = ["aa 250 eu", "bb 250eu", "cc 250 euro", "dd 250euro", 
                  "ee eu 250", "ff eu250",  "gg eur250",  "hh euro250"]
    

    Next we try out the regexps:

    puts test_input.map { |s| 
      # First gsub handles eur before number, second gsub handles eur after number
      s.gsub(/(eu|euro?)\s?(\d+)/, 'euro \2').
        gsub(/(\d+)\s?(eu|euro?)(\z|\s)/, '\1 euro') 
    }
    

    Explanation:

    • \d+ matches 1 or more digits (number)
    • \s? matches zero or 1 whitespace
    • \z matches end of string

    Result:

    aa 250 euro
    bb 250 euro
    cc 250 euro
    xx 250 euro
    dd euro 250
    ee euro 250
    ff euro 250
    
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