Question

I have a string like this:

std::string string1 = "xjdfhfakdjs%54k34k.-jk34";

I need to get only “”xjdfhfakdjs”, but the string is dynamic, not hardcoded so I don’t know what is it, the length etc. so I wanted to remove everything after %, and also the % char.

How could I do this?

Answer 1

I believe that will work.

std::string mystr = string1.substr(0, string1.find("%", 0));