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Home/ Questions/Q 6169655
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T22:53:37+00:00 2026-05-23T22:53:37+00:00

I have a string, my $element=abc#$def I escape # using, $element=~s/#/\\#/g; It is printed

  • 0

I have a string,

my $element="abc#$def"

I escape # using,

 $element=~s/#/\\#/g;

It is printed as: abc\#$def, which is perfect.

Next part of the code is:

push(@arr,$element);
foreach $val (@arr)
{
 print $val;
}

And the value printed within the foreach loop is: abc#$def.

Why is # not escaped here? And how can I retain the escaping?

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  1. Editorial Team
    Editorial Team
    2026-05-23T22:53:38+00:00Added an answer on May 23, 2026 at 10:53 pm

    You’re not quite showing us everything. To get your claimed result, I had to create the variable $def initialized as shown below. But, when I do that, I get the result you expect, not the result you show.

    $ cat xx.pl
    use strict;
    use warnings;
    
    my $def = '$def';
    my $element = "abc#$def";
    
    $element =~ s/#/\\#/g;
    
    print "$element\n";
    
    my @arr;
    
    push(@arr, $element);
    foreach my $val (@arr)
    {
        print $val;
        print "\n";
    }
    
    $ perl xx.pl
    abc\#$def
    abc\#$def
    $
    

    This was tested with Perl 5.14.1 on MacOS X 10.6.8, but I don’t think the behaviour would vary with any other version of Perl 5.

    Given this, can you update your question to show a script similar to mine (in particular, with both use strict; and use warnings;) but which produces the result you show?

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