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Home/ Questions/Q 799379
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:07:00+00:00 2026-05-14T23:07:00+00:00

I have a string named s_Result which will be parsed from the Internet. The

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I have a string named s_Result which will be parsed from the Internet. The format may be "Distance: 2.8km (about 9 mins)", and there are 4 variables which are f_Distance, m_DistanceUnit, f_timeEst, m_timeEstUnit.

My question is how to parse s_Result and assign 2.8, km, 9, mins into f_Distance, m_distanceUnit, f_timeEst and m_timeEstUnit respectively using regular expression?

I tried using "\d+(\.\d+)?" in RegEx Tester and the result showed 2 matches found, but if I use "\\d+(\\.\\d+)?" in Android code, it showed no matches!

Any suggestions what might be going wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-14T23:07:01+00:00Added an answer on May 14, 2026 at 11:07 pm

    Something like that?

    String s_Result="Distance: 2.8km (about 9 mins)";
    
    //Distance parsing
    Pattern p = Pattern.compile("Distance: (\\d+(\\.\\d+)?)(.*?)\\b");
    Matcher m = p.matcher(s_Result);
    if(m.find()){
        MatchResult mr=m.toMatchResult();
        f_Distance=mr.group(1);//2.8
        m_DistanceUnit=mr.group(3);//km
    }
    
    //Time parsing
    p = Pattern.compile("about (\\d+(\\.\\d+)?) (.*)\\b");
    m = p.matcher(s_Result);
    if(m.find()){
        MatchResult mr=m.toMatchResult();
        f_timeEst=mr.group(1);//9
        m_timeEstUnit=mr.group(3);//min
    }
    

    And here’s another option for you, to match more flexible format:

    String s_Result="Distance: 2.8km (about 9 mins)";
    Pattern p = Pattern.compile("(\\d+(\\.\\d+)?) ?(\\w+?)\\b");
    Matcher m = p.matcher(s_Result);
    while(m.find()){
        MatchResult mr=m.toMatchResult();
        String value=mr.group(1);//2.8 and 9 come here
        String units=mr.group(3);//km and mins come here
    }
    
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