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Home/ Questions/Q 9235287
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:59:31+00:00 2026-06-18T06:59:31+00:00

I have a string representing a regex str = [A-z]\Z; I want to replace

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I have a string representing a regex str = "[A-z]\Z";
I want to replace \Z with $ as \Z is not supported in javascript regex.

Is there a way to do this? I tried a few string replace by creating a regex for \Z but they don’t work as expected. It also works on any occurrence of Z. Is there a way to achieve this?
Here is my sample code which has issue

var expression = "[abczZ]\Z";
var regEx = new RegExp("\\Z", "g"); 
a=  expression.replace(regEx, "\\s");
alert(a);
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  1. Editorial Team
    Editorial Team
    2026-06-18T06:59:33+00:00Added an answer on June 18, 2026 at 6:59 am

    You need one additional layer of escaping:

    var regEx = new RegExp("\\\\Z", "g");
    

    because you give the regex as a string, so one escape layer will be “eaten” by the string, retaining only \Z for the regex, which matches a literal Z.

    You can also use a regex literal, in which case you don’t need to double-escape:

    var regEx = /\\Z/g;
    

    Of course, to test it on your string you first need to fix your string. As it stands it does not contain any backslash at all. var expression = "[abczZ]\Z" results in expression containing the string "[abczZ]Z" because you did not escape the backslash. Exact same problem as described in the first two paragraphs.

    Try it yourself in the JS console:

    > "[abczZ]\Z"
    "[abczZ]Z"
    > "[abczZ]\\Z"
    "[abczZ]\Z"
    > "[abczZ]\Z".replace(new RegExp("\\\\Z", "g"), "$")
    "[abczZ]Z"
    > "[abczZ]\\Z".replace(new RegExp("\\\\Z", "g"), "$")
    "[abczZ]$"
    
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