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Home/ Questions/Q 6356625
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T22:59:54+00:00 2026-05-24T22:59:54+00:00

I have a string say: s = ‘deviceId={servicename.DeviceID}&deviceGroupID={servicename.GroupID}&abcd=dkef’ I could get the data by

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I have a string say:

s = 'deviceId={servicename.DeviceID}&deviceGroupID={servicename.GroupID}&abcd=dkef'

I could get the data by parsing several XMLs for the items in Parentheses. After obtaining the data, I use dictset’s combinator to yield these results(roughly) for the items in parantheses {} :

['ApplC3LDJXGEDCP7', '10']
['ApplC3LDJXGEDCP7', '11']
['ApplC3LDJXGEDCP7', '12']
['ApplC3LDJXGEDCP7', '13']
['androidc1596699510', '14']

Dictset combinations return a list of items [deviceId, groupID]. Considering that I am a newbie to Python, how do I iterate over this list and find/replace items in the string? Please help!

Let me also add what I have tried so far- I could iterate over the list using For and able to replace 1 item from the list using re.sub. However the code needs both the items to be replaced at once. The regex i use is
r”{.+?}”

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  1. Editorial Team
    Editorial Team
    2026-05-24T22:59:55+00:00Added an answer on May 24, 2026 at 10:59 pm

    Use single sub call and pass a function that returns what you need.

    s = 'deviceId={servicename.DeviceID}&deviceGroupID={servicename.GroupID}&abcd=dkef'
    r = ['ApplC3LDJXGEDCP7', '10']
    print(re.sub(r'{.+?}', lambda match: r.pop(0), s, count=len(r)))
    # deviceId=ApplC3LDJXGEDCP7&deviceGroupID=10&abcd=dkef
    

    A better approach may be to use urllib.parse.parse_qs, that will tolerate parameter reordering, missing parameters, etc.

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