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Asked: 2026-06-18T15:29:52+00:00

I have a string such as this… test_test_test:Hello \Hello\ Hello,Oh_yea_oh_yea,Hi there buddy I want

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I have a string such as this…

"test_test_test":"Hello \"Hello\" Hello","Oh_yea_oh_yea","Hi there buddy"

I want to grab 

"test_test_test":"Hello \"Hello\" Hello"

So far my regex is this…

"test_test_test":

This would grab the key and colon. I will always know what "test_test_test" is, I just won’t know what the value is after the colon. It would be easy if I knew there wouldn’t be escaped quotations inside the quotations themselves, but there are. Thanks!

EDIT:

There can be commas inside, and there cannot be a quotation that’s not escaped inside.

My idea is something along the lines of…

"test_test_test":"[^(",)]*

In my head, this says keep going until you find the single quotation followed by a comma, (“,) then stop. However that doesn’t work above.

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1 Answer

  1. Editorial Team

    This is the RAW regex. You may need to add more escape if you put into string or include a separator.

    "test_test_test":"(?:[^"\\]|\\[\\"])*"

    If you need flexible spacing:

    "test_test_test" *: *"(?:[^"\\]|\\[\\"])*"

    The key part is here: (?:[^"\\]|\\[\\"])*. It will match 0 or more of: non-quote-or-backslash, or escaped quote \" or escaped backslash \\.

    The regex above is still imprecise: the content in the quoted string is allowed to span multiple lines. Whether it is good or not depends on the grammar for the quoted string. However, multi-line quoted string in the languages I have seen usually doesn’t take the form described in my regex.

    The regex also treats the quoted string "\n" as invalid. You can easily modify the regex a bit to accommodate those cases, though.

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