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Home/ Questions/Q 6803817
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:23:26+00:00 2026-05-26T19:23:26+00:00

I have a string that I need to keep subtracting from the beginning while

  • 0

I have a string that I need to keep subtracting from the beginning while the letters continuously move as well. For example:

ABC DEF GHI JK needs to look like this
BCD EFG HIJ K and then
CDE FGH IJK

I have some code, but the letters are not moving individually:

int main()
{
    string code, default_Code;
    default_Code = "TCAATGTAACGCGCTACCCGGAGCTCTGGGCCCAAATTTCATCCACT";         
    start_C = "AUG";
    code.reserve(100);
    int i = 0, a = 0, c =0;
    char choice;

    for (int j = 3; j < code.length(); j += 4)   // Creating space between 3 letters
    {
        code.insert(j, 1, ' ');
    }

    do {
        i = 0;
        do {                                                // Looping to create an open reading frame.
            for (int b = 0; b*3 < code.length(); b++) {         //  moving through the code 
                for (int a = 0; a < 3; a++) {
                    cout << code[(a + b*3) + i];
                }
            }
            i++;
            cout << endl;
        } while (i < 3);

        reverse(code.rbegin(), code.rend());            // Reversing to create the second set reading frame.

        c++;
        cout << endl; 

    } while (c < 2);
    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:23:26+00:00Added an answer on May 26, 2026 at 7:23 pm

    If you really want to put space characters into the string, instead of just inserting them in the output, you could do something like this:

    std::string code("TCAATGTAACGCGCTACCCGGAGCTCTGGGCCCAAATTTCATCCACT");
    
    // a repeating pattern of offsets
    int x[4] = { 1, 1, 2, 0 };
    
    for (size_t i = 3; i < code.length(); i +=4)
    {
        code.insert(i, 1, ' ');
    }
    
    while (code.length() > 0)
    {
        printf("%s\n", code.c_str());
    
        for (size_t i = 0; i < code.length() - 1; i++)
        {
            // new char is either 1, 2, or 0 bytes ahead
            size_t j = i + x[i % 4];
    
            // in case it's 2 bytes at the end, just get the last
            code[i] = code[j < code.length() ? j : j - 1];
        }
    
        // and throw away the leftover at the end
        code.resize(code.length() - 1);
    }
    

    EDIT> To respond to the comments below:

    If you try inserting this code before the printf statement…

        size_t t = code.find("ATC");
        if (t != std::string::npos)
        {
            code.replace(t, 3, " M ");
        }
    

    …you’ll see that code.find(“ATC”) does not find “A TC” or “AT C”. It doesn’t find it until the third line of output when “ATC” appears in the string without any spaces in between the letters. I have spaces inserted the actual string data just as your original code did.

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