Question

I have a string that looks like the following:

“01/11/2012 (Last, First) – Notes,02/11/2012 (Last, First) – More Notes,03/11/2012 (Last, First) – Even More Notes,09/12/2012 (Last, First) – You get the idea”

I would like each note to fall on a new line by replacing any comma followed by a number with ‘\n’.

I have tried .replace(/,/g, '\n') but I get a newline in the middle of the name.
So I do .replace(/,\d/g, '\n'), however then I loose the first number of the date.

How can I search for ,# and replace it with \n# where the number is the same as it was previously?

I want the result to look like this:

01/11/2012 (Last, First) - Notes
02/11/2012 (Last, First) - More Notes
03/11/2012 (Last, First) - Even More Notes
09/12/2012 (Last, First) - You get the idea

Answer 1

You can use a capture to avoid missing that number:

s.replace(/,(\d)/g, '\n$1')