Question

I have a String which contains numbers in a comma separated form. and I want to extract the most appears numbers from the String.
For example I have a String like..

String str="1,2,3,4,5,6,7,19,18,4";

from the above str i need 4 because 4 is two times in str.

same as

String str2="1,2,3,4,6,4,3,9";

from the above str2 i need 3,4

In case of all numbers are unique then i need first one.

suggest me better approach.

Answer 1

Try Below Code

public class StringCheck {
    public static void main(String args[]) {
        String input = "1,2,3,4,5,6,2,3,4,1,4,33,33,33";
        String result = "";
        String[] arr1 = input.split(",");

        System.out.println("Input is : " + input);

        for (int i = 0; i < arr1.length; i++) {
            int k = 0;
            for (int j = 0; j < arr1.length; j++) {
                if (arr1[i].equals(arr1[j])) {
                    k++;
                    if (k == 2) {
                        if (result.contains(arr1[i])) {
                            break;
                        }
                        result = result + arr1[i] + ",";
                        break;
                    }
                }
            }
        }

        System.out.println("Result is " + result);
    }
}    

Below will be output

Input is : 1,2,3,4,5,6,2,3,4,1,4,33,33,33
Result is 1,2,3,4,33,

Let me know if there are any queries…

Cheers!!!