Question

I have a string with a length that is a multiple of 8 that contains only 0’s and 1’s. I want to convert the string into a byte array suitable for writing to a file. For instance, if I have the string ‘0010011010011101’, I want to get the byte array [0x26, 0x9d], which, when written to file, will give 0x269d as the binary (raw) contents.

How can I do this in Python?

Answer 1

py> data = '0010011010011101' py> data = [data[8*i:8*(i+1)] for i in range(len(data)/8)] py> data ['00100110', '10011101'] py> data = [int(i, 2) for i in data] py> data [38, 157] py> data = ''.join(chr(i) for i in data) py> data '&\x9d'