Question

I have a StringBuffer,strbuf=161656070200000000202020202001000000009E52;.

I want to convert into a byte array that looks like this:

byte[] byte_array=new byte[]
 {(byte)0x16,(byte)0x16,(byte)0x56,(byte)0x07,
  (byte)0x02,(byte)0x00,(byte)0x00,(byte)0x00,
  (byte)0x00,(byte)0x20,(byte)0x20,(byte)0x20,
  (byte)0x20,(byte)0x20,(byte)0x01,(byte)0x00,
  (byte)0x00,(byte)0x00,(byte)0x00,(byte)0x9E,(byte)0x52};

Do I need to convert strbuf to hex string and then do getBytes()?
What is the right approach to this problem?

Answer 1

You can try the following.

final String longHex = "161656070200000000202020202001000000009E52";
byte[] bytes = new BigInteger(longHex, 16).toByteArray();
System.out.println(Arrays.toString(bytes));

prints

[22, 22, 86, 7, 2, 0, 0, 0, 0, 32, 32, 32, 32, 32, 1, 0, 0, 0, 0, -98, 82]