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Home/ Questions/Q 8586973
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T22:27:00+00:00 2026-06-11T22:27:00+00:00

I have a struct that contains an unsigned char * for storing arbitrary data.

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I have a struct that contains an unsigned char * for storing arbitrary data. At some point I want to use this data as if it were a two-dimensional array. This is how I do it:

#define DATA_SIZE 10
unsigned char *data = malloc(DATA_SIZE * DATA_SIZE * sizeof(unsigned char));

// this is not allowed
unsigned char (* matrix)[DATA_SIZE] = (unsigned char*[DATA_SIZE]) &data;

// this gives a warning and doesn't work at all
unsigned char (* matrix)[DATA_SIZE] = (unsigned char **) &data;

I want to cast a pointer to arbitrary data to a two-dimesional array, but of course I can’t cast to array types. How would I need to go about this?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-11T22:27:02+00:00Added an answer on June 11, 2026 at 10:27 pm

    You have gotten the syntax of the cast wrong,

    unsigned char (* matrix)[DATA_SIZE] = (unsigned char(*)[DATA_SIZE]) data;
    

    works after you fixed your #define by removing the =.

    #define DATA_SIZE 10
    
        unsigned char *data = malloc(DATA_SIZE * DATA_SIZE * sizeof(unsigned char));
    
        // this is the correct way to cast
        unsigned char (* matrix)[DATA_SIZE] = (unsigned char(*)[DATA_SIZE]) data;
    
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