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Home/ Questions/Q 858657
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:34:17+00:00 2026-05-15T08:34:17+00:00

I have a struct with an array of 100 int (b) and a variable

  • 0

I have a struct with an array of 100 int (b) and a variable of type int (a)

I have a function that checks if the value of “a” is in the array and i have generated the array elements and the variable with random values.

but it doesn’t work
can someone help me fix it?

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

typedef struct {
    int a;
    int b[100];
} h;

int func(h v){
    int i;

    for (i=0;i<100;i++){
        if(v.b[i]==v.a) 
            return 1;
        else 
            return 0;
    }

}

int main(int argc, char** argv)
{
    h str;
    srand(time(0)); 
    int i;
    for(i=0;0<100;i++){
        str.b[i]=(rand() % 10) + 1;
    }
    str.a=(rand() % 10) + 1;
    str.a=1;

    printf("%d\n",func(str));

    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-15T08:34:17+00:00Added an answer on May 15, 2026 at 8:34 am

    Your check function returns after the first loop iteration. So unless the value you’re looking for is the first element of the array, it returns 0 and never checks the rest of the array. The ‘return 0’ needs to be outside the body of the loop

    for (i=0;i<100;i++){
        if(v.b[i]==v.a) 
            return 1;
    }
    return 0; 
    

    Additionally, the for loop in main() checks to see if 0<100 (which will pretty much always be true…)

    for(i=0;0<100;i++){
        str.b[i]=(rand() % 10) + 1;
    }
    

    Should be:

    for(i=0;i<100;i++){
        str.b[i]=(rand() % 10) + 1;
    }
    
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