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Home/ Questions/Q 6550189
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:11:10+00:00 2026-05-25T12:11:10+00:00

I have a Structure say MyStruct:- #define SEC_DIMENSION 2 struct MyStruct { char cChar;

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I have a Structure say MyStruct:-

#define SEC_DIMENSION 2
struct MyStruct
{
  char cChar;
  float fFloat;
  int   iInt;
};

struct MyStruct StructArray[SEC_DIMENSION][20];  //Two Dimensional Array of Structures.

Now I want to access this with Pointer.

struct MyStruct *StructPtr[SEC_DIMENSION];

I did assignment as follows:-

 StructPtr[0] = &StructArray[0][0];

Now, I want to access Members of Structure StructArray[0][1] i.e. StructArray[0][1].cChar or StructArray[0][1].fFloat

How can I access them by using StructPtr?

I tried using StuctPtr[0][1]->cChar then ((StructPtr[0])[1])->cChar
Both returned an error.

With StructPtr[0]->cChar build was successful. But this is not what I want.

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:11:10+00:00Added an answer on May 25, 2026 at 12:11 pm

    “Now I want to access this with Pointer” is not very descriptive. What you have in your example will not work. What you declared is not a pointer to an array but rather an array of pointers. Is that what you need? I don’t know.

    If you really need a pointer to an array, you can declare your pointer it as

    struct MyStruct (*StructPtr)[20];
    

    and then make it point to your array as

    StructPtr = StructArray;
    

    From this point on you can access the original array through this pointer as StructPtr[i][j]

    StructPtr[i][j].cChar = 'a';
    

    Alternatively, you can declare the pointer as

    struct MyStruct (*StructPtr)[SEC_DIMENSION][20];
    

    and then make it point to your array as

    StructPtr = &StructArray;
    

    From this point on you can access the original array through this pointer as (*StructPtr)[i][j]

    (*StructPtr)[i][j].cChar = 'a';
    
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