Question

I have a structure with fields ID,Coor,Misc,Conn. ID and Misc are doubles, however, Coor is a 1×3 vector and Conn is a 1xn vector (where n can theoretically be from 0 to inf).

Point(x).ID = [x]
Point(x).Coordinate = [xPos yPos zPos]
Point(x).Misc = [randomDouble]
Point(x).Conn = [someVectorOfNumbers]

I would like to have this mapped on a cell array, without using a FOR loop.

An example of the output:

'ID    xPos    yPos    zPos    Misc    Conn'
 1      0        0       0       0    '0 1 2'
 2      1        1       1       1      ''     
 ...
 x      x        x       x       x      '2'

Notice that Point.Conn, its vector of numbers gets converted into a string.

The issues that I am having is breaking up Point.Coordinate into its three elements, and converting Point.Conn into a string.

I feel like this can be done using struct2Cell and then changing the nesting level. I’m just not exactly sure how to do that.

Answer 1

First make some example data:

n = 10;

ID         = num2cell(randperm(n)');
Coordinate = mat2cell(randn(n, 3), ones(n,1));
Misc       = num2cell(randn(n,1));
Conn       = arrayfun(@randperm, randperm(n), 'UniformOutput', 0)';

Point = struct('ID', ID, 'Coordinate', Coordinate, 'Misc', Misc, 'Conn', Conn);

Now inspect it:

>> Point

Point = 

10x1 struct array with fields:
    ID
    Coordinate
    Misc
    Conn

>> Point(1)

ans = 

            ID: 7
    Coordinate: [-0.0571 -1.1645 2.4124]
          Misc: 0.0524
          Conn: [3 2 1]

Now use arrayfun() to sweep through the elements of structure array Point. We define a generic function x to operate on each element of Point, formatting the row like you described:

Point_cell = arrayfun(@(x) [num2cell([x.ID x.Coordinate x.Misc]) num2str(x.Conn)], Point, 'UniformOutput', 0);
Point_cell = vertcat(Point_cell{:})

Now inspect the output:

ans = 

    [ 7]    [-0.0571]    [-1.1645]    [ 2.4124]    [ 0.0524]    '3  2  1'            
    [ 5]    [ 0.2918]    [ 0.4948]    [ 0.7402]    [-1.9539]    '1  2'               
    [ 3]    [-0.6146]    [-1.2158]    [ 0.3097]    [ 0.5654]    '3  4  1  2'         
    [10]    [-0.0136]    [ 1.5908]    [-0.5420]    [ 0.0778]              [1x25 char]
    [ 2]    [ 0.4121]    [ 0.5265]    [ 0.1223]    [ 0.0807]              [1x22 char]
    [ 1]    [-0.9371]    [ 0.2648]    [ 0.9623]    [ 0.7947]    '1  2  5  4  3'      
    [ 4]    [ 0.8352]    [-0.3936]    [-0.2540]    [ 1.0437]    '6  2  3  7  4  1  5'
    [ 8]    [ 1.0945]    [-2.1763]    [ 1.8918]    [ 0.8022]    '1'                  
    [ 6]    [ 0.3212]    [-1.1957]    [-1.2203]    [-0.4688]              [1x37 char]
    [ 9]    [ 0.0151]    [ 0.3653]    [-0.3762]    [-0.0466]    '3  5  4  2  6  1'   

Couldn’t tell from your question, but if you want all the numeric fields as an array inside a single cell, that is an easy tweak to do. Good luck!