Question

I have a submit button when i click on that button i am having jQuery function which sends the Request to server side script

$('#submit_button').click(function(){
    $('#MYdialog').dialog('open');
    alert("Request Submitting");

    $.getJSON("test.php?stcode=<?php echo $this->stcode;?>",
        $("#myform").serialize(),
        function(data){
            $.ajaxSetup ({ cache: false});
            $('#MYdialog').dialog('close');

            alert(data);

            if ( data.num != null ) {
                window.open('print_test.php?stcode=01&no=' + data.num );
                window.location = self.location;
            }
        });
    }       
}); 

When i submit the request the mysubmit Dialog opened and running in loop. How do debug what is happening at server side script?

Answer 1

I highly recommend FirePHP – it allows you to put out debug messages from your PHP code that don’t alter your actual response: everything gets added to the headers.