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Home/ Questions/Q 659747
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:04:45+00:00 2026-05-13T23:04:45+00:00

I have a super fish menu, the delay is set to 800, but when

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I have a super fish menu, the delay is set to 800, but when I move from one drop-down to another it still shows the previous drop-down and the new drop-down at the same time. until the 800ms delay is over then the previous drop-down goes away. I do not want to change the delay, but if a new drop-down is opened, I want the previously opened drop-down to close right away without delay. I hope this makes sense.

Is there a way to do that?

Thanks!!

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:04:45+00:00Added an answer on May 13, 2026 at 11:04 pm

    On its website, delay is set to 800 and I guess it works fine, it doesn’t display old popup. Did you make any other changes in its code?

    http://users.tpg.com.au/j_birch/plugins/superfish/#examples

    Edit:
    Ok here is a solution if you don’t want to modify your multiple UL menu structure to a single UL. Just give unique ids to each UL, then modify over = function() in superfish.js like this

    over = function(){
        var $$ = $(this), menu = getMenu($$);
        $('.sf-menu').each(function(){
            if ($(this).attr('id') != $(menu).attr('id')) {
                $(this).hideSuperfishUl();
            }                       
        });
        clearTimeout(menu.sfTimer);
        $$.showSuperfishUl().siblings().hideSuperfishUl();
    },
    

    this may cause some other side effects but I don’t see any for now.

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