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Home/ Questions/Q 7651921
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T11:37:39+00:00 2026-05-31T11:37:39+00:00

I have a table ‘Asset’ with a column ‘AssetDescription’. Every row of it has

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I have a table ‘Asset’ with a column ‘AssetDescription’. Every row of it has some group of words/sentences, seprated by comma.

row1: – flowers, full color, female, Trend
row2:- baby smelling flowers, heart

Now if a put a search query like:-

select * from Asset where contains(AssetDescription,'flower')

It returns nothing.

I have one more table ‘SearchData’ with column ‘SearchCol’, having similar rows as mentioned above in table ‘Asset’. Now if a put a search query like:-

select * from SearchData where contains(SearchCol,'flower')

It returns both the rows.

QUESTION:-

  1. Why first query doesn’t return any result, but second one does correctly.

  2. If ‘Full Text Search’ has something to do with 1st ques, than what to do regarding that. As I’m using SQL server 2000.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T11:37:40+00:00Added an answer on May 31, 2026 at 11:37 am

    CONTAINS requires a full text search index, and for full text search indexing to be enabled.
    LIKE doesn’t require full text search.

    The advantage of using CONTAINS over LIKE is that CONTAINS is more flexible and potentially a lot faster. LIKE may require a full table scan depending how you use it.

    From the SQL Server docs

    In contrast to full-text search, the LIKE Transact-SQL predicate works
    on character patterns only. Also, you cannot use the LIKE predicate to
    query formatted binary data. Furthermore, a LIKE query against a large
    amount of unstructured text data is much slower than an equivalent
    full-text query against the same data. A LIKE query against millions
    of rows of text data can take minutes to return; whereas a full-text
    query can take only seconds or less against the same data, depending
    on the number of rows that are returned.

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