Question

I have a table called player and after inserting the data into there, which successfully works, I have the following piece of code to capture the value of the auto incremented primary key.

$one = $pdo->lastInsertId();

What I then wish to do is to take the value that is stored in this variable and insert it as a value in another table. I have tried a couple of ways but to no avail. Please see below:

ATTEMPT ONE

try
{
    $sql = "INSERT INTO links SET
            link = :link,
            playerid = '$one'";
    $s = $pdo->prepare($sql);
    $s->bindValue(':link', $_POST['link']);
    $s->bindValue(':playerid', $_POST[':playerid']);
    $s->execute();
}
catch (PDOException $e)
{
    $error = 'Error adding link for player.' . $e->getMessage();
    include 'error.html.php';
    exit();
}

ATTEMPT TWO

try
{
    $sql = 'INSERT INTO links SET
            link = :link,
            playerid = :playerid';
    $s = $pdo->prepare($sql);
    $s->bindValue(':link', $_POST['link']);
    $s->bindValue(':playerid', $_POST['$one']);
    $s->execute();
}
catch (PDOException $e)
{
    $error = 'Error adding link for player.' . $e->getMessage();
    include 'error.html.php';
    exit();
}

The code doesn’t actually throw any errors but when I look in the database, the value is not getting passed in.

Can anyone explain what is going wrong please?

Thanks for your time and help.

Answer 1

just use $one

$sql = 'INSERT INTO links SET
        link = :link,
        playerid = :playerid';
$s = $pdo->prepare($sql);
$s->bindValue(':link', $_POST['link']);
$s->bindValue(':playerid', $one);