Question

I have a table called “profile” in mysql database
Table structure:

user | hasimg | imgurl

As you can see “hasimg” and “imgurl”, normally if a user does not have an image, hasimg will be set to 0 and imgurl is set to none.

On the other hand, if a user has an image assigned then hasimg is set to 1 and imgurl will contain the link.

• How can I display ones that have images (hasimg set to 1) with <img src="imgurl html tags?

• How can I display ones that do not have images (hasimg set to 0) , without <img src?

I want to make a list which display users with images and user that does not have image.

Here’s the code im using to echo out the data row by row

   <?php

      $sql = "SELECT * FROM profile ORDER BY user DSC"; 
      $query = mysql_query($sql)or die(mysql_error());

               $rows = array();
        while($row = mysql_fetch_array( $query )){
          $rows[] = $row;
          echo "User:$row[user]<br>Image:$row[hasimg]\n";
        }

    ?>

P/S mysql connection established.

Answer 1

If you want to keep your layout fancy way you can use default image.

if($hasimg == 0)
   $imgurl = "default.jpg";

echo '<img src="' . $imgurl . '">';

EDIT:

Your PHP code could be like this.

 $sql = "SELECT * FROM profile ORDER BY user DSC"; 
 $result = mysql_query($sql)or die(mysql_error());


echo "<table border='1'>
<tr>
<th>Name</th>
<th>Image</th>
</tr>";

while($row = mysql_fetch_array($result))
  {
    $imgurl = $row['imgurl'];
    if($row['hasimg'] == 0)
         $imgurl = "default.jpg";

      echo "<tr>";
      echo "<td>" . $row['user'] . "</td>";
      echo "<td><img src=\"" .$imgurl . "'\" /></td>";
      echo "</tr>";
  }
echo "</table>";