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Home/ Questions/Q 7894827
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T07:29:36+00:00 2026-06-03T07:29:36+00:00

I have a table containing foodjoint data with their latitude and longitude. I am

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I have a table containing foodjoint data with their latitude and longitude.

I am using this query

 $q = "SELECT (
              (ACOS(SIN( ".$userLatitude." * PI() / 180) * SIN(foodjoint_latitude * PI() / 180) + COS(".$userLongitude." * PI() / 180) * COS(foodjoint_longitude * PI() / 180) * COS((foodjoint_longitude - ".$longitude.") * PI() / 180)) * 180 / PI()) * 60 * 1.1515 * 1.609344) AS distance
             , foodjoint_id
             , foodjoint_name
             , open_hours
             , cont_no
             , AVG(customer_ratings) AS rating
             , address_line
             , city 

          FROM provider_food_joints,customer_review HAVING distance <=3";

$userLatitude and $userLongitude is the users location.I want the distance to be compared in km. thnx in advance.
I want to display the foodjoint data under 3 km radious.

when I just running it doesn’t select any row.but with out this having condition it fetches all the records.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T07:29:38+00:00Added an answer on June 3, 2026 at 7:29 am

    I found some code in a project of mine, but i’m not sure about the distance calculation.. You should improve your JOIN though.. What are the tables joining on?

    $q = "SELECT (
                        (
                            (
                                ACOS(
                                    SIN(".$userLatitude." * PI() / 180) * 
                                    SIN(foodjoint_latitude * PI() / 180) + 
    
                                    COS(".$userLatitude." * PI() / 180) * 
                                    COS(foodjoint_latitude * PI() / 180) *
                                    COS(
                                        (".$userLongitude." - foodjoint_longitude) * PI() / 180)
                                    ) * 
                                180 / PI()
                            ) * 60 * (1.1515*1.609344)
                        ) AS distance
    
               , foodjoint_id
               , foodjoint_name
               , open_hours
               , cont_no
               , AVG(customer_ratings) AS rating
               , address_line
               , city 
    
            FROM provider_food_joints,customer_review 
          HAVING distance < 4";
    
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