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Home/ Questions/Q 8667839
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:04:13+00:00 2026-06-12T18:04:13+00:00

I have a table defined as this: CREATE TABLE A_TEST ( ID NUMBER NOT

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I have a table defined as this:

CREATE TABLE A_TEST  (
    "ID"   NUMBER NOT NULL ENABLE,
    "TYPE" VARCHAR2(20 BYTE),
)
  • ID is not a primary key.
  • TYPE might be NULL
  • An ID I can have 0, 1 or more TYPEs.

if I want to get IDs with differents types I will write this query:

SELECT distinct a1.ID FROM A_TEST a1
  JOIN A_TEST a2 on a2.ID = a1.ID and a2.type != a1.type

But how can I find Ids for which I have a single type defined?
(only one row for Id or many rows for id with only one having a type defined)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T18:04:14+00:00Added an answer on June 12, 2026 at 6:04 pm

    After the clarifications, it seems that your requirements are:

    SELECT ID
    FROM A_TEST
    GROUP BY ID    
    HAVING COUNT(DISTINCT TYPE) = 1
        OR COUNT(*) = 1 ;
    
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