Question

I have a table

ID | DATE
1  |  16-01-2012
2  |  17-01-2012
3  |  18-01-2012
4  |  22-01-2012
5  |  28-01-2012
6  |  02-02-2012

My task is:

I have a date variable which is initialised to 16-01-2012 and I have to find all rows which are in continuum with 16-01-2012 i.e 17-01-2012 and 18-01-2012.

Please help.

Answer 1

One possibility would be to use a hierarchical query like the following:

with data (id, date)
as
(
    select id, date from yourtable where date = '16-01-2012'
    UNION ALL
    select t.id, t.date
    from yourtable t
    inner join data d 
      on  DATEDIFF(dd, d.date, t.date) = 1
    -- 1 day difference
)
select
    *
from
    data
;

I don’t have an SQL server here to try this out, so there might be some errors in the statement. It should give you an idea though.