Question

I have a table

id   type       left    right 
1    featured   1       2 
2    default    3       1 
3    default    5       2 
4    default    2       7 
5    featured   3       4 
6    featured   3       2 
7    day        1       3
8    default    12      42

I need output five id where type != day and sort it by sum(left + right) and sort it by featured, default

First, need all the featured type ORDERING by sum(left + right), than with type = dafule ordering by sum(left + right) LIMIT 5

What I want to get:

5, 6, 1, 8, 4

Thanks!

Answer 1

The sort by “Featured” coming first is the IF() in the order by… if the type is “featured”, then use 1 as the sort basis, otherwise, use 2. Since you only have featured and default available (restricting “day” entries). Otherwise, that would be changed to a CASE/WHEN construct to account for other types

select
      yt.id,
      yt.type,
      yt.left + yt.right as LeftPlusRight
   from 
      YourTable yt
   where
      yt.type <> 'day'
   order by
      if( yt.type = 'featured', 1, 2 ),
      LeftPlusRight  DESC
   limit 5